Difference between revisions of "Bend Path"
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The following text was originally written by J.F. Barraud. It explains the mathematics behind the Bend Path effect. | |||
Let B be the skeleton path, and P the pattern (the path to be deformed). | |||
P is a map t --> P(t) = ( x(t), y(t) ) and B is a map t --> B(t) = ( a(t), b(t) ) | |||
The first step is to re-parametrize B by its arc length: this is the parametrization in which a point p on B is located by its distance s from start. We obtain a new map s --> U(s) = (a'(s),b'(s)), that still describes the same path B, but where the distance along B from start to U(s) is s itself. | |||
We also need a unit normal to the path. This can be obtained by computing a unit tangent vector, and rotate it by 90°. We call this normal vector N(s). | |||
The basic deformation associated to B is then given by: | |||
(x,y) --> U(x)+y*N(x) | |||
(i.e. we go for distance x along the path, and then for distance y along the normal) | |||
Revision as of 09:35, 28 May 2008
The following text was originally written by J.F. Barraud. It explains the mathematics behind the Bend Path effect.
Let B be the skeleton path, and P the pattern (the path to be deformed).
P is a map t --> P(t) = ( x(t), y(t) ) and B is a map t --> B(t) = ( a(t), b(t) )
The first step is to re-parametrize B by its arc length: this is the parametrization in which a point p on B is located by its distance s from start. We obtain a new map s --> U(s) = (a'(s),b'(s)), that still describes the same path B, but where the distance along B from start to U(s) is s itself. We also need a unit normal to the path. This can be obtained by computing a unit tangent vector, and rotate it by 90°. We call this normal vector N(s).
The basic deformation associated to B is then given by:
(x,y) --> U(x)+y*N(x)
(i.e. we go for distance x along the path, and then for distance y along the normal)